Given below are two statements:Statement-I: I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the Hofmann bromamide degradation reaction,an amide reacts with bromine in an alkaline medium to form a primary amine.The mechanism involves th

Vedclass · Accepted Answer

Statement-$I$ is incorrect but Statement-$II$ is correct

Vedclass · Answer

(D) In the Hofmann bromamide degradation reaction,an amide reacts with bromine in an alkaline medium to form a primary amine.The mechanism involves the formation of an $N$-bromamide intermediate,which loses a proton to form an electron-deficient nitrene-like species (or nitrenoid intermediate).During the rearrangement,the alkyl or aryl group $(R)$ migrates from the carbonyl carbon to the electron-deficient nitrogen atom to form an isocyanate $(R-N=C=O)$.Statement-$I$ is incorrect because not only alkyl groups but also aryl groups can migrate.Statement-$II$ is correct because the migration occurs specifically to the electron-deficient nitrogen atom.Therefore,Statement-$I$ is incorrect and Statement-$II$ is correct.

Similar Questions

Benzamide reacts with $Br_2$ and $KOH$ gives :-

The correct order of increasing basic nature for the bases $NH_{3}$,$CH_{3}NH_{2}$ and $(CH_{3})_{2}NH$ in aqueous solutions is:

Which of the following is the strongest base?

Which of the following amines undergoes acylation reaction?

The major products obtained from the following sequence of reactions are
$(CH_3)_2CHCH_2N(CH_2CH_3)_2$ $\xrightarrow{CH_3I}$ $\xrightarrow[H_2O]{Ag_2O}$ $\xrightarrow{\Delta} \text{products}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module