(B) To find the frictional force applied by the wall on block $B$,we consider the system of both blocks $A$ and $B$ in equilibrium.Since the system is

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(B) To find the frictional force applied by the wall on block $B$,we consider the system of both blocks $A$ and $B$ in equilibrium.Since the system is in equilibrium,the total downward gravitational force must be balanced by the upward frictional force exerted by the wall on block $B$.The total weight of the system is $W_{total} = W_A + W_B = 20\ N + 100\ N = 120\ N$.Let $f_{wall}$ be the frictional force exerted by the wall on block $B$.For the system to be in vertical equilibrium,the upward force must equal the downward force:$f_{wall} = W_{total} = 120\ N$.Thus,the frictional force applied by the wall on block $B$ is $120\ N$.

Class 11 Physics Laws of Motion Mix Examples-Newton's Laws of Motion and Friction

Medium

Given in the figure are two blocks $A$ and $B$ of weight $20\ N$ and $100\ N,$ respectively. These are being pressed against a wall by a force $F$ as shown. If the coefficient of friction between the blocks is $0.1$ and between block $B$ and the wall is $0.15$,the frictional force applied by the wall on block $B$ is ........... $N$.

JEE MAIN 2015 All JEE MAIN

A
$80$
B
$120$
C
$150$
D
$100$

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Class 11

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Laws of Motion

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Mix Examples-Newton's Laws of Motion and Friction

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$A$ small ball $B$ of mass $m$ is suspended with a light inelastic string of length $L$ from a block $A$ of the same mass $m$,which can move on a smooth horizontal surface as shown in the figure. The ball is displaced by an angle $\theta$ from the equilibrium position and then released. The tension in the string when it is vertical is:

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$STATEMENT-1$: It is easier to pull a heavy object than to push it on a level ground.
$STATEMENT-2$: The magnitude of frictional force depends on the nature of the two surfaces in contact.

MediumIIT 2008

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$A$ cold soft drink is kept on a balance. When the cap is opened,the weight reading on the balance:

Easy

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$A$ uniform cylinder rests on a cart as shown. The coefficient of static friction between the cylinder and the cart is $0.5$. If the cylinder is $4\, cm$ in diameter and $10\, cm$ in height,which of the following is the minimum acceleration of the cart needed to cause the cylinder to tip over? (Assume $g = 10\, m/s^2$)

Difficult

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$A$ boy of mass $4 \, kg$ is standing on a piece of wood having mass $5 \, kg$. If the coefficient of friction between the wood and the floor is $0.5$,the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is ...... $N$. (Round off to the Nearest Integer) [Take $g = 10 \, m s^{-2}$]

DifficultJEE MAIN 2021

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$STATEMENT-1$: It is easier to pull a heavy object than to push it on a level ground.$STATEMENT-2$: The magnitude of frictional force depends on the nature of the two surfaces in contact.

$A$ cold soft drink is kept on a balance. When the cap is opened,the weight reading on the balance:

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$STATEMENT-1$: It is easier to pull a heavy object than to push it on a level ground.
$STATEMENT-2$: The magnitude of frictional force depends on the nature of the two surfaces in contact.