Given that sin theta = frac{a}{b}, then cos t | vedclass

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(D) Given,$\sin 	heta = \frac{a}{b}$.Using the trigonometric identity $\sin^{2} 	heta + \cos^{2} 	heta = 1$,we can write $\cos 	heta = \sqrt{1 - \

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$\frac{\sqrt{b^{2}-a^{2}}}{b}$

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(D) Given,$\sin 	heta = \frac{a}{b}$.Using the trigonometric identity $\sin^{2} 	heta + \cos^{2} 	heta = 1$,we can write $\cos 	heta = \sqrt{1 - \sin^{2} 	heta}$.Substituting the value of $\sin 	heta$:$\cos 	heta = \sqrt{1 - \left(\frac{a}{b}ight)^{2}}$$\cos 	heta = \sqrt{1 - \frac{a^{2}}{b^{2}}}$$\cos 	heta = \sqrt{\frac{b^{2} - a^{2}}{b^{2}}}$$\cos 	heta = \frac{\sqrt{b^{2} - a^{2}}}{b}$.

Given that $\sin \theta = \frac{a}{b},$ then $\cos \theta$ is equal to

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