(B) Given,$\sin \alpha = \frac{1}{2} = \sin 30^{\circ}$ $\left[\because \sin 30^{\circ} = \frac{1}{2}\right]$$\Rightarrow \alpha = 30^{\circ}$And,$\co

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(B) Given,$\sin \alpha = \frac{1}{2} = \sin 30^{\circ}$ $\left[\because \sin 30^{\circ} = \frac{1}{2}\right]$$\Rightarrow \alpha = 30^{\circ}$And,$\cos \beta = \frac{1}{2} = \cos 60^{\circ}$ $\left[\because \cos 60^{\circ} = \frac{1}{2}\right]$$\Rightarrow \beta = 60^{\circ}$Therefore,$\alpha + \beta = 30^{\circ} + 60^{\circ} = 90^{\circ}$

Class 10 Mathematics Introduction to Trigonometry Trigonometric Ratios of Some Specific Angles

Easy

Given that $\sin \alpha = \frac{1}{2}$ and $\cos \beta = \frac{1}{2}$,then the value of $(\alpha + \beta)$ is (in $^{\circ}$)

A
$0$
B
$90$
C
$30$
D
$60$

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Class 10

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Chapter

Introduction to Trigonometry

Subtopic

Trigonometric Ratios of Some Specific Angles

If $\sin \theta = \frac{1}{2}$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^\circ$)

Easy

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If $\tan 2A = \cot(A - 18^{\circ})$,where $2A$ is an acute angle,find the value of $A$ (in $^{\circ}$).

Medium

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Evaluate:
$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$

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In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $m \angle A = 60^{\circ}$. If $AC = 10$,then $AB = \dots$

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$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

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Given that $\sin \alpha = \frac{1}{2}$ and $\cos \beta = \frac{1}{2}$,then the value of $(\alpha + \beta)$ is (in $^{\circ}$)

Similar Questions

If $\sin \theta = \frac{1}{2}$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^\circ$)

If $\tan 2A = \cot(A - 18^{\circ})$,where $2A$ is an acute angle,find the value of $A$ (in $^{\circ}$).

Evaluate:$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$

In $\Delta ABC$,$m \angle B = 90^{\circ}$ and $m \angle A = 60^{\circ}$. If $AC = 10$,then $AB = \dots$

$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

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Evaluate:
$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$