Glycol on treatment with $PI_3$ mainly gives -

The rate of hydration of the following compounds will be in the order:

Find out the major product of the following reaction:
$2 \text{ mole } CH_2=CH-CH_2Br \xrightarrow{Mg, T.H.F.} \text{?}$

Identify $C$ in the following series $C_3H_7I$ $\xrightarrow[alc.]{KOH} A$ $\xrightarrow[\Delta]{NBS} B$ $\xrightarrow[alc.]{KCN} C$.

Compound $X$ on reaction with $O_{3}$ followed by $Zn/H_{2}O$ gives formaldehyde and $2-$methylpropanal as products. The compound $X$ is :

The reaction of the compound $(CH_3)_2C = CH-CH_3$ with $NaIO_4$ in the presence of $KMnO_4$ yields: