Half the perimeter of a rectangular garden,whose length is $4 \, m$ more than its width,is $36 \, m$. Represent this as a pair of linear equations in two variables.

(N/A) Let the length of the rectangular garden be $x \, m$ and the width be $y \, m$.
According to the problem,the length is $4 \, m$ more than its width:
$x = y + 4$
$x - y = 4$ ...... $(1)$
The perimeter of a rectangle is $2(x + y)$.
Therefore,half the perimeter is $\frac{2(x + y)}{2} = x + y$.
Given that the half perimeter is $36 \, m$:
$x + y = 36$ ...... $(2)$
Thus,the pair of linear equations in two variables representing the given situation is:
$x - y = 4$
$x + y = 36$