Hardness of water is 200 ppm. Calculate the | vedclass

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(A) $200 \ ppm$ means $200 \ g$ of $CaCO_3$ in $10^6 \ g$ (or approximately $10^6 \ mL$) of water.$	ext{Molar mass of } CaCO_3 = 40 + 12 + (3 	imes

Vedclass · Accepted Answer

$2 	imes 10^{-3} \ M ; 4 	imes 10^{-3} \ N$

Vedclass · Answer

(A) $200 \ ppm$ means $200 \ g$ of $CaCO_3$ in $10^6 \ g$ (or approximately $10^6 \ mL$) of water.$	ext{Molar mass of } CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$.$	ext{Molarity} = \frac{	ext{mass in } g}{	ext{Molar mass}} 	imes \frac{1000}{V_{mL}} = \frac{200}{100} 	imes \frac{1000}{10^6} = 2 	imes 10^{-3} \ M$.$	ext{Equivalent mass of } CaCO_3 = \frac{	ext{Molar mass}}{n	ext{-factor}} = \frac{100}{2} = 50 \ g/eq$.$	ext{Normality} = \frac{	ext{mass in } g}{	ext{Equivalent mass}} 	imes \frac{1000}{V_{mL}} = \frac{200}{50} 	imes \frac{1000}{10^6} = 4 	imes 10^{-3} \ N$.

Hardness of water is $200 \ ppm$. Calculate the molarity and normality of $CaCO_3$ in the water.

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