(C) The heat of neutralization is defined as the heat released when $1 \ mol$ of $H^+$ ions reacts with $1 \ mol$ of $OH^-$ ions to form $1 \ mol$ of

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(C) The heat of neutralization is defined as the heat released when $1 \ mol$ of $H^+$ ions reacts with $1 \ mol$ of $OH^-$ ions to form $1 \ mol$ of $H_2O$.Given,$\Delta H_{neut} = -57.1 \ kJ \ mol^{-1}$ for $1 \ mol$ of reaction.For $0.25 \ mol$ of $NaOH$ reacting with $0.25 \ mol$ of $HCl$,the amount of heat released is calculated as:$\text{Heat released} = \Delta H_{neut} \times \text{moles of reaction}$$\text{Heat released} = 57.1 \ kJ \ mol^{-1} \times 0.25 \ mol = 14.275 \ kJ \approx 14.3 \ kJ$.

Class 11 Chemistry Thermodynamics Heat of reaction, Bond energy and Hess law

Medium

The heat of neutralization for the reaction $NaOH + HCl \to NaCl + H_2O$ is $57.1 \ kJ \ mol^{-1}$. What will be the heat released when $0.25 \ mol$ of $NaOH$ is titrated against $0.25 \ mol$ of $HCl$ (in $kJ$)?

A
$22.5$
B
$57.1$
C
$14.3$
D
$28.6$

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Thermodynamics

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Heat of reaction, Bond energy and Hess law

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(Nearest integer)

MediumJEE MAIN 2021

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The enthalpy change $(\Delta H)$ for the neutralisation of $1 \ M \ HCl$ by caustic potash in dilute solution at $298 \ K$ is ..... $kJ$.

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The standard heats of formation in $kcal \ mol^{-1}$ of $NO_{2(g)}$ and $N_2O_{4(g)}$ are $8.0$ and $2.0$ respectively. The heat of dimerization of $NO_2$ in $kcal$ for the reaction $2NO_{2(g)} \rightarrow N_2O_{4(g)}$ is:

Medium

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The heat of neutralization for the reaction $NaOH + HCl \to NaCl + H_2O$ is $57.1 \ kJ \ mol^{-1}$. What will be the heat released when $0.25 \ mol$ of $NaOH$ is titrated against $0.25 \ mol$ of $HCl$ (in $kJ$)?

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The enthalpies of combustion of $C(s)$, $H_2(g)$, and $CH_4(g)$ are $-390 \text{ kJ/mol}$, $-285 \text{ kJ/mol}$, and $-890 \text{ kJ/mol}$ respectively. Calculate the enthalpy of formation of methane $(CH_4)$.

If the standard molar enthalpy change for combustion of graphite powder is $-2.48 \times 10^{2} \ kJ \ mol^{-1}$,the amount of heat generated on combustion of $1 \ g$ of graphite powder is $..... \ kJ$.(Nearest integer)

The enthalpy change $(\Delta H)$ for the neutralisation of $1 \ M \ HCl$ by caustic potash in dilute solution at $298 \ K$ is ..... $kJ$.

The total enthalpy change in a chemical reaction is equal to the algebraic sum of the enthalpy changes of the individual steps of the reaction. This statement is associated with which scientist?

The standard heats of formation in $kcal \ mol^{-1}$ of $NO_{2(g)}$ and $N_2O_{4(g)}$ are $8.0$ and $2.0$ respectively. The heat of dimerization of $NO_2$ in $kcal$ for the reaction $2NO_{2(g)} \rightarrow N_2O_{4(g)}$ is:

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If the standard molar enthalpy change for combustion of graphite powder is $-2.48 \times 10^{2} \ kJ \ mol^{-1}$,the amount of heat generated on combustion of $1 \ g$ of graphite powder is $..... \ kJ$.
(Nearest integer)