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(A) Given wavelength $\lambda = 900 \ nm = 900 	imes 10^{-7} \ cm = 9 	imes 10^{-5} \ cm$. Rydberg constant $R_{H} = 10^5 \ cm^{-1}$. Using Rydberg

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Paschen series,$\infty \rightarrow 3$

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(A) Given wavelength $\lambda = 900 \ nm = 900 	imes 10^{-7} \ cm = 9 	imes 10^{-5} \ cm$. Rydberg constant $R_{H} = 10^5 \ cm^{-1}$. Using Rydberg equation for $H$-atom $(Z=1)$: $\frac{1}{\lambda} = R_{H} 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$. Substituting the values: $\frac{1}{9 	imes 10^{-5}} = 10^5 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2})$. $\frac{1}{9} = \frac{1}{n_1^2} - \frac{1}{n_2^2}$. For this equality to hold,$n_1 = 3$ and $n_2 = \infty$. This corresponds to the Paschen series transition from $\infty ightarrow 3$.

List-$I$	List-$II$
$(1)$ Exclusion Principle	$(A)$ Hund
$(2)$ Multiplicity Rule	$(B)$ Heisenberg
$(3)$ Uncertainty Principle	$(C)$ Einstein
$(4)$ Quantum Theory	$(D)$ Planck
	$(E)$ Pauli

Heat treatment of muscular pain involves radiation of wavelength of about $900 \ nm$. Which spectral line of $H$ atom is suitable for this? Given: Rydberg constant $R_{H}=10^5 \ cm^{-1}, h=6.6 \times 10^{-34} \ J \ s, c=3 \times 10^8 \ m / s$.

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List-$I$ List-$II$

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$(E)$ Pauli

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