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(D) geostationary satellite orbits the Earth with a time period $T = 24 \, 	ext{hours} = 86400 \, 	ext{s}$.
Using the formula for the orbital radiu

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$36000$

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(D) geostationary satellite orbits the Earth with a time period $T = 24 \, 	ext{hours} = 86400 \, 	ext{s}$.
Using the formula for the orbital radius $r$ of a satellite: $r = \left( \frac{G M T^2}{4 \pi^2} ight)^{1/3}$.
Given $GM = g R^2$,where $g = 9.8 \, 	ext{m/s}^2$ and $R = 6.4 	imes 10^6 \, 	ext{m}$,the orbital radius $r$ is approximately $42200 \, 	ext{km}$.
The height $h$ above the Earth's surface is $h = r - R$.
$h = 42200 \, 	ext{km} - 6400 \, 	ext{km} = 35800 \, 	ext{km}$.
Rounding to the nearest standard value,the height is approximately $36000 \, 	ext{km}$.

The height of a geostationary satellite is approximately ........ $km$.

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