Helium diffuses four times faster than which | vedclass

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(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r_1/r_2 = \s

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$SO_2$

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(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r_1/r_2 = \sqrt{M_2/M_1}$.Given $r_{He}/r_x = 4$,where $M_{He} = 4 \ g/mol$.Substituting the values: $4 = \sqrt{M_x/4}$.Squaring both sides: $16 = M_x/4$.Therefore,$M_x = 16 	imes 4 = 64 \ g/mol$.Comparing the molar masses of the options:$M(ClO_2) = 35.5 + 2(16) = 67.5 \ g/mol$$M(SO_2) = 32 + 2(16) = 64 \ g/mol$$M(CO_2) = 12 + 2(16) = 44 \ g/mol$$M(NO_2) = 14 + 2(16) = 46 \ g/mol$The gas with a molar mass of $64 \ g/mol$ is $SO_2$.

Helium diffuses four times faster than which of the following?

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