Hex-1-yne on reaction with Br_2 (excess)/ CCl | vedclass

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(D) The reaction of an alkyne with excess $Br_2$ in $CCl_4$ is an electrophilic addition reaction. During this process,both $\pi$-bonds of the triple

Vedclass · Accepted Answer

$1,1,2,2-$Tetrabromohexane

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(D) The reaction of an alkyne with excess $Br_2$ in $CCl_4$ is an electrophilic addition reaction. During this process,both $\pi$-bonds of the triple bond are broken,and four new $\sigma$-bonds are formed with bromine atoms. For hex$-1-$yne $(CH_3(CH_2)_3C \equiv CH)$,the addition occurs at the $C-1$ and $C-2$ positions. The final product is $1,1,2,2-$tetrabromohexane. $CH_3(CH_2)_3C \equiv CH + 2Br_2 \xrightarrow{CCl_4} CH_3(CH_2)_3C(Br)_2-CH(Br)_2$

Hex$-1-$yne on reaction with $Br_2$ (excess)/ $CCl_4$,gives

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