Hot wire ammeters are used for measuring

$A$ light bulb is rated at $100\;W$ for a $220\;V$ supply. Find
$(a)$ the resistance of the bulb;
$(b)$ the peak voltage of the source; and
$(c)$ the rms current through the bulb.

An alternating current in a circuit is given by $I = 20 \sin (100 \pi t + 0.05 \pi) \ A$. The r.m.s. value and the frequency of the current respectively are:

If the value of potential in an $AC$ circuit is $10 \ V$,then the peak value of potential is

$100\text{ W}$ रेटेड एक प्रकाश बल्ब $220\text{ V}$, $50\text{ Hz}$ के $AC$ स्रोत से जुड़ा है। बल्ब से प्रवाहित होने वाली $rms$ धारा है: (in $text{ A}$)

An electric current has both $DC$ and $AC$ components. The $DC$ component is $8 \ A$ and the $AC$ component is given as $I = 6 \sin \omega t$. The $rms$ value of the resultant current is . . . . . . (in $A$)