How does the mean free path vary with the num | vedclass

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(B) The mean free path $\lambda$ of gas molecules is given by the formula $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the mo

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Inversely proportional

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(B) The mean free path $\lambda$ of gas molecules is given by the formula $\lambda = \frac{1}{\sqrt{2} \pi d^2 n}$,where $d$ is the diameter of the molecule and $n$ is the number density of the gas molecules.From this relation,it is clear that the mean free path $\lambda$ is inversely proportional to the number density $n$ of the gas molecules,i.e.,$\lambda \propto \frac{1}{n}$.

How does the mean free path vary with the number density of a gas?

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