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(B) The resistance $R$ of a conductor is given by the formula $R = \rho \frac{L}{A}$,where $\rho$ is the resistivity,$L$ is the length,and $A$ is the

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It is inversely proportional to the cross-sectional area.

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(B) The resistance $R$ of a conductor is given by the formula $R = \rho \frac{L}{A}$,where $\rho$ is the resistivity,$L$ is the length,and $A$ is the cross-sectional area of the wire.From this relation,it is clear that the resistance $R$ is inversely proportional to the cross-sectional area $A$ $(R \propto \frac{1}{A})$.Therefore,as the cross-sectional area increases,the resistance of the wire decreases.

How does the resistance of a wire vary with its cross-sectional area?

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