How many H atoms are present in 0.046 , g of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The molecular weight of ethanol $(C_2H_5OH)$ is $2 	imes 12 + 6 	imes 1 + 16 = 46 \, g/mol$. One molecule of $C_2H_5OH$ contains $6$ hydrogen at

Vedclass · Accepted Answer

$3.6 	imes 10^{21}$

Vedclass · Answer

(D) The molecular weight of ethanol $(C_2H_5OH)$ is $2 	imes 12 + 6 	imes 1 + 16 = 46 \, g/mol$. One molecule of $C_2H_5OH$ contains $6$ hydrogen atoms. Number of moles of $C_2H_5OH = \frac{0.046 \, g}{46 \, g/mol} = 0.001 \, mol = 10^{-3} \, mol$. Number of molecules of $C_2H_5OH = 10^{-3} 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{20}$. Number of $H$ atoms = $6 	imes (6.022 	imes 10^{20}) \approx 3.6 	imes 10^{21}$.

How many $H$ atoms are present in $0.046 \, g$ of ethanol $(C_2H_5OH)$?

Similar Questions

If the amplitude of $z-2-3i$ is $\frac{\pi}{4}$,then the locus of $z=x+iy$ is:

The volume of the tetrahedron formed by the coterminous edges $\vec{a}, \vec{b}, \vec{c}$ is $3$. Then the volume of the parallelepiped formed by the coterminous edges $\vec{a} + \vec{b}, \vec{b} + \vec{c}, \vec{c} + \vec{a}$ is

The colour of the bead in the borax bead test is mainly due to the formation of:

The melting point of $Zn$ is lower as compared to those of the other elements of the $3d$ series because:

$\frac{(1+i)^{2011}}{(1-i)^{2009}}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module