How many 3-digit numbers can be formed using | vedclass

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(D) To form a $3$-digit number,we have three positions: the hundreds place,the tens place,and the units place.$1$. The hundreds place cannot be $0$ be

Vedclass · Accepted Answer

$100$

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(D) To form a $3$-digit number,we have three positions: the hundreds place,the tens place,and the units place.$1$. The hundreds place cannot be $0$ because a $3$-digit number cannot start with $0$. The available digits are ${2, 3, 5, 7}$. Thus,there are $4$ choices for the hundreds place.$2$. The tens place can be any of the given digits ${0, 2, 3, 5, 7}$ since repetition is allowed. Thus,there are $5$ choices for the tens place.$3$. The units place can also be any of the given digits ${0, 2, 3, 5, 7}$ since repetition is allowed. Thus,there are $5$ choices for the units place.Total number of $3$-digit numbers $= 4 	imes 5 	imes 5 = 100$.

How many $3$-digit numbers can be formed using $0, 2, 3, 5, 7$ when repetition is allowed?

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