How many mL of perhydrol is required to produ | vedclass

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(A) Perhydrol is a $30\% \ w/v$ $H_2O_2$ solution, which corresponds to $100$ volume $H_2O_2$. This means $1 \ mL$ of perhydrol produces $100 \ mL$ of

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(A) Perhydrol is a $30\% \ w/v$ $H_2O_2$ solution, which corresponds to $100$ volume $H_2O_2$. This means $1 \ mL$ of perhydrol produces $100 \ mL$ of $O_2$ at $STP$. The reaction for conversion is: $2SO_2 + O_2 \rightarrow 2SO_3$. From the stoichiometry, $2 \ L$ of $SO_2$ requires $1 \ L$ of $O_2$ for complete conversion. Volume of $O_2$ required = $1 \ L = 1000 \ mL$. Therefore, volume of perhydrol required = $\frac{1000 \ mL}{100} = 10 \ mL$.

How many $mL$ of perhydrol is required to produce sufficient oxygen which can be used to completely convert $2 \ L$ of $SO_2$ gas to $SO_3$ gas (in $mL$)?

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