How many NAND gates are used to form an AND g | vedclass

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(B) To form an $AND$ gate using $NAND$ gates,we need two $NAND$ gates.First,the inputs $A$ and $B$ are fed into the first $NAND$ gate,which produces a

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(B) To form an $AND$ gate using $NAND$ gates,we need two $NAND$ gates.First,the inputs $A$ and $B$ are fed into the first $NAND$ gate,which produces an output of $\overline{A \cdot B}$.This output is then fed into the second $NAND$ gate,which acts as a $NOT$ gate (since its inputs are shorted together).The final output $Y$ is given by:$Y = \overline{(\overline{A \cdot B}) \cdot (\overline{A \cdot B})} = \overline{\overline{A \cdot B}} = A \cdot B$Thus,two $NAND$ gates are required to realize an $AND$ gate.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$0$

How many $NAND$ gates are used to form an $AND$ gate?

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