How many electrons can fit in the orbital for which $n = 3$ and $l = 1$?

Each orbital has a nodal plane. Which of the following statements about nodal planes are not true:

In a multi-electron atom,which of the following orbitals have the same energy in the absence of magnetic and electric fields? $(a) n = 1, l = 0, m = 0, (b) n = 3, l = 0, m = 0, (c) n = 2, l = 1, m = 1, (d) n = 3, l = 2, m = 1, (e) n = 3, l = 2, m = 0$

Given below are the quantum numbers for $4$ electrons.
$A. \; n = 3, l = 2, m_l = 1, m_s = +1/2$
$B. \; n = 4, l = 1, m_l = 0, m_s = +1/2$
$C. \; n = 4, l = 2, m_l = -2, m_s = -1/2$
$D. \; n = 3, l = 1, m_l = -1, m_s = +1/2$
The correct order of increasing energy is

The $d$ orbital with the orientation along $X$ and $Y$ axis is called.

What will be the maximum number of electrons in any atom having quantum numbers $n = 4, l = 2, m = -2$?