How many geometrical isomers are possible for | vedclass

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(B) The complex $[Pd^{2+} (NH_2-CH(CH_3)-CO_2^-)_2]$ involves a bidentate ligand,alanine $(NH_2-CH(CH_3)-CO_2^-)$,which is unsymmetrical.For a square

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$3$

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(B) The complex $[Pd^{2+} (NH_2-CH(CH_3)-CO_2^-)_2]$ involves a bidentate ligand,alanine $(NH_2-CH(CH_3)-CO_2^-)$,which is unsymmetrical.For a square planar complex of the type $[M(AB)_2]$,where $AB$ is an unsymmetrical bidentate ligand,there are $3$ possible geometrical isomers.These are:$1$. $cis$-isomer where the two $N$ atoms are adjacent and the two $O$ atoms are adjacent.$2$. $trans$-isomer where the two $N$ atoms are opposite and the two $O$ atoms are opposite.$3$. Another $cis$-isomer where the arrangement of the chiral centers relative to each other differs.Thus,there are $3$ geometrical isomers possible.

How many geometrical isomers are possible for $[Pd^{2+} (NH_2-CH(CH_3)-CO_2^-)_2]$?

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