How many geometrical isomers are possible for | vedclass

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Question

(A) The complex $[Mab(AB)_2]^{n \pm}$ consists of a central metal atom $M$,two monodentate ligands $a$ and $b$,and two unsymmetrical bidentate ligands

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The complex $[Mab(AB)_2]^{n \pm}$ consists of a central metal atom $M$,two monodentate ligands $a$ and $b$,and two unsymmetrical bidentate ligands $(AB)$.For this type of octahedral complex,the geometrical isomers are determined by the relative positions of the ligands.There are $6$ possible geometrical isomers for this complex,as shown in the provided structural diagrams: $2$ cis-forms and $4$ trans-forms.Therefore,the total number of geometrical isomers is $6$.

How many geometrical isomers are possible for the complex $[Mab(AB)_2]^{n \pm}$?

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