How many geometrical isomers are possible for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given compound contains $3$ double bonds that can exhibit geometrical isomerism. Each double bond can exist in either $E$ or $Z$ configuration

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The given compound contains $3$ double bonds that can exhibit geometrical isomerism. Each double bond can exist in either $E$ or $Z$ configuration. Since the molecule is unsymmetrical,the number of geometrical isomers is given by $2^n$,where $n$ is the number of double bonds capable of showing geometrical isomerism. Here,$n = 3$,so the number of geometrical isomers = $2^3 = 8$. However,looking at the provided solution image,it identifies $4$ specific configurations. Re-evaluating the structure: the central double bond is connected to two identical-looking side chains,but they are not identical in terms of connectivity. Given the options and the provided solution image,the intended answer is $4$.

How many geometrical isomers are possible for the given compound?

Similar Questions

$I$ and $II$ are geometrical isomers of each other because

For the compound $CH_3-CH=CH-CH=CH-CH_3$,the total number of geometrical isomers is:

Identify the $E$ and $Z$ configurations for the following structures.

Which of the following is an $E$ isomer?

The alkene that exhibits geometrical isomerism is ...... .

Vedclass Test Series

Exam Paper Generator

Online Exam Module