How many geometrical isomers are possible for | vedclass

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(A) The given compound is $1,1,2$-trimethylcyclohexane. For a compound to exhibit geometrical isomerism,there must be restricted rotation (like in a r

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) The given compound is $1,1,2$-trimethylcyclohexane. For a compound to exhibit geometrical isomerism,there must be restricted rotation (like in a ring or double bond) and each of the two carbons involved in the restricted rotation must be attached to two different groups. In $1,1,2$-trimethylcyclohexane,the carbon at position $1$ is attached to two identical methyl $(-CH_3)$ groups. Since one of the carbons in the ring (the $C-1$ atom) does not have two different groups attached to it,it cannot exhibit geometrical isomerism. Therefore,the number of geometrical isomers possible for this compound is $0$.

How many geometrical isomers are possible for the compound shown in the image?

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