How many geometrical isomers are possible in the following coordination entities?
$(i)$ $[Cr(C_2O_4)_3]^{3-}$
$(ii)$ $[Co(NH_3)_3Cl_3]$

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(N/A) $(i)$ For $[Cr(C_2O_4)_3]^{3-},$ no geometrical isomer is possible because the complex contains three identical symmetrical bidentate ligands,which results in a highly symmetric structure.
$(ii)$ For $[Co(NH_3)_3Cl_3],$ two geometrical isomers are possible: the facial $(fac)$ isomer,where the three identical ligands occupy the corners of one triangular face of the octahedron,and the meridional $(mer)$ isomer,where the three identical ligands occupy the positions around the meridian of the octahedron.

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The magnetic moments of the following,arranged in decreasing order,will be:-
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$(iv)$ $Co^{2+}$ (Square planar complex)

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Change in composition of the coordination sphere yields which type of isomers?

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How can the isomeric complexes $[Co(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_6][Co(NO_2)_6]$ be distinguished from one another?

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