How many grams of HCl will be present in 150 | vedclass

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(A) The molarity $(M)$ is defined as the number of moles of solute per liter of solution. The formula is $M = \frac{w}{m 	imes V(L)}$,where $w$ is th

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$2.84$

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(A) The molarity $(M)$ is defined as the number of moles of solute per liter of solution. The formula is $M = \frac{w}{m 	imes V(L)}$,where $w$ is the mass in grams,$m$ is the molar mass of $HCl$ $(36.5 \ g/mol)$,and $V(L)$ is the volume in liters. Given: $M = 0.52 \ M$,$V = 150 \ mL = 0.15 \ L$,and $m = 36.5 \ g/mol$. Substituting the values: $0.52 = \frac{w}{36.5 	imes 0.15}$. Calculating $w$: $w = 0.52 	imes 36.5 	imes 0.15 = 2.847 \ g \approx 2.84 \ g$.

How many grams of $HCl$ will be present in $150 \ mL$ of its $0.52 \ M$ solution?

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