How many grams of carbon dioxide gas are diss | vedclass

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(B) According to Henry's Law,the solubility of a gas in a liquid is given by $P = K_H 	imes x$,where $P$ is the partial pressure of the gas,$K_H$ is

Vedclass · Accepted Answer

$1.95$

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(B) According to Henry's Law,the solubility of a gas in a liquid is given by $P = K_H 	imes x$,where $P$ is the partial pressure of the gas,$K_H$ is Henry's law constant,and $x$ is the mole fraction of the gas in the solution.Given: $P = 2.4 \ atm$,$K_H = 3000 \ atm$.$x = \frac{P}{K_H} = \frac{2.4}{3000} = 8 	imes 10^{-4}$.Since the solution is dilute,the number of moles of water in $1 \ L$ $(1000 \ g)$ is $n_{H_2O} = \frac{1000}{18} \approx 55.56 \ mol$.The mole fraction $x = \frac{n_{CO_2}}{n_{CO_2} + n_{H_2O}} \approx \frac{n_{CO_2}}{n_{H_2O}}$.Therefore,$n_{CO_2} = x 	imes n_{H_2O} = (8 	imes 10^{-4}) 	imes 55.56 \approx 0.0444 \ mol$.The mass of $CO_2$ is $n_{CO_2} 	imes 	ext{molar mass} = 0.0444 \ mol 	imes 44 \ g/mol \approx 1.95 \ g$.

How many grams of carbon dioxide gas are dissolved in $1 \ L$ of carbonated water,if the manufacturer uses a pressure of $2.4 \ atm$ in the bottling process at $25^{\circ} C$ (in $g$)? ($K_{H}$ of $CO_2 = 3000 \ atm$)

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