How many isomers (cyclic and acyclic) are pos | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The degree of unsaturation $(DU)$ for $C_3H_6O$ is calculated as: $DU = C + 1 - \frac{H}{2} = 3 + 1 - \frac{6}{2} = 1$. This indicates the presenc

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) The degree of unsaturation $(DU)$ for $C_3H_6O$ is calculated as: $DU = C + 1 - \frac{H}{2} = 3 + 1 - \frac{6}{2} = 1$. This indicates the presence of either one double bond or one ring. Possible acyclic isomers: $1$. Propanal $(CH_3CH_2CHO)$ $2$. Propanone $(CH_3COCH_3)$ $3$. Allyl alcohol $(CH_2=CH-CH_2OH)$ $4$. $1$-propen$-1-$ol $(CH_3-CH=CH-OH)$ $5$. $2$-propen$-1-$ol $(CH_2=C(OH)-CH_3)$ $6$. Methoxyethene $(CH_3-O-CH=CH_2)$ Possible cyclic isomers: $7$. Cyclopropanol $8$. Methoxycyclopropane (Oxetane is not possible as it has $4$ atoms in ring,but $C_3H_6O$ can form $2$-methyloxirane or oxetane) $9$. $2$-methyloxirane (propylene oxide) $10$. Oxetane Wait,let us list them carefully: $(1)$ Propanal,$(2)$ Propanone,$(3)$ Allyl alcohol $(CH_2=CHCH_2OH)$,$(4)$ $1$-propen$-1-$ol $(CH_3CH=CHOH)$,$(5)$ $2$-propen$-1-$ol $(CH_2=C(OH)CH_3)$,$(6)$ Methoxyethene $(CH_3OCH=CH_2)$,$(7)$ Cyclopropanol,$(8)$ $2$-methyloxirane,$(9)$ Oxetane. Total isomers = $9$.

How many isomers (cyclic and acyclic) are possible for a compound with molecular formula $C_3H_6O$?

Similar Questions

Determine the correct configuration of the following molecule:

The number of stereoisomers formed by the given compound is

Which of the following compounds is most stable?

Which of the following is the least stable conformer of cyclohexane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module