How many molecules of carbon dioxide are form | vedclass

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Question

(A) The chemical equation for the combustion of carbon is: $C + O_2 \rightarrow CO_2$ From the stoichiometry of the reaction,$12 \ g$ of $C$ produces

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$3.01 	imes 10^{22}$

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(A) The chemical equation for the combustion of carbon is: $C + O_2 ightarrow CO_2$ From the stoichiometry of the reaction,$12 \ g$ of $C$ produces $44 \ g$ of $CO_2$. Therefore,$0.6 \ g$ of $C$ will produce: $\frac{44 	imes 0.6}{12} = 2.2 \ g$ of $CO_2$. The molar mass of $CO_2$ is $44 \ g/mol$. Number of moles of $CO_2 = \frac{2.2 \ g}{44 \ g/mol} = 0.05 \ mol$. Number of molecules of $CO_2 = 	ext{moles} 	imes N_A = 0.05 	imes 6.022 	imes 10^{23} = 3.011 	imes 10^{22}$ molecules.

How many molecules of carbon dioxide are formed when $0.6 \ g$ carbon is burnt in air?

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