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(B) To find the number of pairs of letters in the word $PENCIL$ that have as many letters between them as in the English alphabet,we check the sequenc

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One

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(B) To find the number of pairs of letters in the word $PENCIL$ that have as many letters between them as in the English alphabet,we check the sequence:$1$. $P$ to $E$: $P(16), E(5)$. Difference is $11$. No match.$2$. $P$ to $N$: $P(16), N(14)$. Difference is $2$. No match.$3$. $P$ to $C$: $P(16), C(3)$. Difference is $13$. No match.$4$. $P$ to $I$: $P(16), I(9)$. Difference is $7$. No match.$5$. $E$ to $N$: $E(5), N(14)$. Letters between in word: $1$ $(N)$. Letters between in alphabet: $8$. No match.$6$. $E$ to $C$: $E(5), C(3)$. Letters between in word: $1$ $(N)$. Letters between in alphabet: $1$ $(D)$. Match found: $(E, C)$.$7$. $E$ to $I$: $E(5), I(9)$. Difference is $4$. No match.$8$. $N$ to $C$: $N(14), C(3)$. No match.$9$. $N$ to $I$: $N(14), I(9)$. No match.$10$. $C$ to $I$: $C(3), I(9)$. Letters between in word: $0$. Letters between in alphabet: $5$. No match.Checking backwards:$1$. $I$ to $C$: $I(9), C(3)$. No match.$2$. $I$ to $N$: $I(9), N(14)$. No match.$3$. $I$ to $E$: $I(9), E(5)$. No match.$4$. $I$ to $P$: $I(9), P(16)$. No match.$5$. $C$ to $N$: $C(3), N(14)$. No match.$6$. $C$ to $E$: $C(3), E(5)$. Match found: $(C, E)$.There is only one pair $(E, C)$ or $(C, E)$ depending on the direction,but the question asks for pairs of letters. In standard reasoning,$(E, C)$ is one pair.Thus,the correct answer is One.

How many pairs of letters are there in the word $PENCIL$ which have as many letters between them in the word as in the alphabet?

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