(A) One molecule of glucose $(C_6H_{12}O_6)$ undergoes glycolysis in the cytoplasm. During this process,the $6$-carbon glucose molecule is broken down

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(A) One molecule of glucose $(C_6H_{12}O_6)$ undergoes glycolysis in the cytoplasm. During this process,the $6$-carbon glucose molecule is broken down into two molecules of $3$-carbon pyruvic acid (pyruvate). Therefore,the oxidation of $1$ glucose molecule yields $2$ molecules of pyruvate.