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(C) The atomic number of cobalt $(Co)$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the $[CoF_6]^{3-}$ complex,the oxidation s

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$4$

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(C) The atomic number of cobalt $(Co)$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the $[CoF_6]^{3-}$ complex,the oxidation state of $Co$ is $x + 6(-1) = -3$,so $x = +3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.In the $3d$ subshell,the $6$ electrons are distributed as follows: one orbital is doubly occupied,and the remaining four orbitals are singly occupied.Therefore,there are $4$ unpaired electrons present in the $Co^{3+}$ ion prior to hybridization.

How many unpaired electrons are present in the cobalt ion in the $+3$ oxidation state prior to hybridization in the $[CoF_6]^{3-}$ complex ion?

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