How much g of NaOH is required to neutralize | vedclass

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(B) The neutralization reaction is $NaOH + HCl \rightarrow NaCl + H_2O$.For neutralization,the number of equivalents of $NaOH$ must equal the number o

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$6$

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(B) The neutralization reaction is $NaOH + HCl ightarrow NaCl + H_2O$.For neutralization,the number of equivalents of $NaOH$ must equal the number of equivalents of $HCl$.Equivalents of $HCl = N 	imes V_{(L)} = 0.1 \, N 	imes 1.5 \, L = 0.15 \, 	ext{equivalents}$.Since the equivalent weight of $NaOH$ is $40 \, g/eq$,the mass of $NaOH$ required is $W = 	ext{Equivalents} 	imes 	ext{Eq. wt.}$.$W = 0.15 	imes 40 = 6 \, g$.

How much $g$ of $NaOH$ is required to neutralize $1500 \, cm^3$ of $0.1 \, N$ $HCl$ (At. wt. of $Na = 23$)?

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