How much time is required for complete decomp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The decomposition reaction of water is $H_2O \rightarrow H_2 + \frac{1}{2}O_2$. In this reaction,the oxidation of $O^{2-}$ to $O_2$ involves $2 \,

Vedclass · Accepted Answer

$1.93 	imes 10^5 \, 	ext{sec}$

Vedclass · Answer

(B) The decomposition reaction of water is $H_2O ightarrow H_2 + \frac{1}{2}O_2$. In this reaction,the oxidation of $O^{2-}$ to $O_2$ involves $2 \, e^-$ per mole of $H_2O$ $(O^{2-} ightarrow \frac{1}{2}O_2 + 2e^-)$. For $4 \, 	ext{moles}$ of water,the total charge $Q$ required is $Q = n 	imes 	ext{moles} 	imes F = 2 	imes 4 	imes 96500 \, 	ext{C} = 772000 \, 	ext{C}$. Using the formula $Q = I 	imes t$,where $I = 4 \, 	ext{A}$,we get $772000 = 4 	imes t$. Therefore,$t = \frac{772000}{4} = 193000 \, 	ext{sec} = 1.93 	imes 10^5 \, 	ext{sec}$.

How much time is required for complete decomposition of $4 \, \text{moles}$ of water using $4 \, \text{A}$ current?

Similar Questions

The required charge for one equivalent weight of silver deposited on cathode is

During the electrolysis of acidified water, $16 \text{ g}$ of $O_2$ gas is formed at the anode. The volume of $H_2$ gas liberated at the cathode under $STP$ conditions is: (in $text{ L}$)

How many seconds of current at $241.25 \ A$ must be passed to deposit all the silver present in $125 \ mL$ of $1 \ M \ AgNO_3$ solution? $(1 \ F = 96500 \ C)$

Two Faraday of electricity is passed through a solution of $CuSO_4$. The mass of copper deposited at the cathode is ......... $g$. (at. mass of $Cu = 63.5 \ amu$)

The approximate time duration in hours to electroplate $30 \ g$ of calcium from molten calcium chloride using a current of $5 \ A$ is [At. mass of $Ca=40$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module