What is the water potential of a fully turgid | vedclass

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(C) The water potential $(\Psi_w)$ of a cell is determined by the sum of solute potential $(\Psi_s)$ and pressure potential $(\Psi_p)$, represented by

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$0$

Vedclass · Answer

(C) The water potential $(\Psi_w)$ of a cell is determined by the sum of solute potential $(\Psi_s)$ and pressure potential $(\Psi_p)$, represented by the equation: $\Psi_w = \Psi_s + \Psi_p$.In a fully turgid cell, the cell wall exerts a pressure (turgor pressure) that is equal and opposite to the osmotic pressure of the cell contents.Therefore, the pressure potential $(\Psi_p)$ becomes equal to the magnitude of the solute potential $(\Psi_s)$ but with a positive sign.Since $\Psi_s$ is always negative, $\Psi_p$ is positive and equal in value to $\Psi_s$.Thus, $\Psi_w = \Psi_s + (-\Psi_s) = 0$.Hence, the water potential of a fully turgid cell is $0$.

What is the water potential of a fully turgid cell?

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