How much work should be done on an object of | vedclass

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(A) Given: Mass $m = 120 \, kg$,initial velocity $u = 25 \, m s^{-1}$,final velocity $v = 40 \, m s^{-1}$.According to the work-energy theorem,the wor

Vedclass · Accepted Answer

$58500$

Vedclass · Answer

(A) Given: Mass $m = 120 \, kg$,initial velocity $u = 25 \, m s^{-1}$,final velocity $v = 40 \, m s^{-1}$.According to the work-energy theorem,the work done $W$ on an object is equal to the change in its kinetic energy.$W = \Delta KE = \frac{1}{2} m (v^2 - u^2)$Substituting the values:$W = \frac{1}{2} 	imes 120 	imes (40^2 - 25^2)$$W = 60 	imes (1600 - 625)$$W = 60 	imes 975$$W = 58500 \, J$Thus,the work done is $58500 \, J$.

How much work should be done on an object of $120 \, kg$ to increase its speed from $25 \, m s^{-1}$ to $40 \, m s^{-1}$ (in $, J$)?

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