Which of the following complexes has its hybr | vedclass

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(C) Let us analyze each complex:$1$. $AuCl_4^-$: $Au^{3+}$ is a $5d^8$ ion. It forms a square planar complex with $dsp^2$ hybridisation.$2$. $[Co(oxal

Vedclass · Accepted Answer

$RhCl(PPh_3)_3 - dsp^2$

Vedclass · Answer

(C) Let us analyze each complex:$1$. $AuCl_4^-$: $Au^{3+}$ is a $5d^8$ ion. It forms a square planar complex with $dsp^2$ hybridisation.$2$. $[Co(oxalato)_3]^{3-}$: $Co^{3+}$ is a $3d^6$ ion. Oxalate is a strong field ligand,leading to inner orbital complex formation with $d^2sp^3$ hybridisation.$3$. $RhCl(PPh_3)_3$: This is Wilkinson's catalyst. $Rh^+$ is a $4d^8$ ion,forming a square planar complex with $dsp^2$ hybridisation.$4$. $[Fe(NH_3)_6]^{2+}$: $Fe^{2+}$ is a $3d^6$ ion. $NH_3$ acts as a strong field ligand for $Fe^{2+}$,resulting in $d^2sp^3$ hybridisation. However,option $C$ is the most standard representation of $dsp^2$ for $Rh(I)$ square planar complexes.

List-$I$ (Hybridisation)	List-$II$ (Compound/ion)
$A. sp^3d$	$I. [PtCl_4]^{2-}$
$B. sp^3d^2$	$II. SF_6$
$C. dsp^2$	$III. BCl_3$
$D. dsp^3$	$IV. PCl_5$
	$V. ClF_3$

List-$I$ (Complex/ion)	List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$	$I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$	$II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$	$III$. Square planar
$D$. $[Fe(CO)_5]$	$IV$. Tetrahedral

Which of the following complexes has its hybridisation correctly matched?

Similar Questions

The hybridization of $Ag^+$ in the linear complex $[Ag(NH_3)_2]^+$ is

Match the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion)
$A. sp^3d$ $I. [PtCl_4]^{2-}$
$B. sp^3d^2$ $II. SF_6$
$C. dsp^2$ $III. BCl_3$
$D. dsp^3$ $IV. PCl_5$
$V. ClF_3$

The correct match is:

Define the following term: Coordination polyhedron.

What will be the type of hybridization if the shapes are square planar,octahedral,and linear,respectively?

Match List-$I$ with List-$II$:
List-$I$ (Complex/ion) List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$ $I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$ $II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$ $III$. Square planar
$D$. $[Fe(CO)_5]$ $IV$. Tetrahedral

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