What is the hybridization of the central I at | vedclass

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(D) To determine the hybridization of the triiodide ion $(I_3^-)$,we use the formula:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (V + M - C

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$sp^3d$

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(D) To determine the hybridization of the triiodide ion $(I_3^-)$,we use the formula:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (V + M - C + A)$Where:$V = 	ext{Number of valence electrons of the central atom} = 7$$M = 	ext{Number of monovalent atoms attached} = 2$$C = 	ext{Cationic charge} = 0$$A = 	ext{Anionic charge} = 1$Substituting the values:$	ext{Number of Hybrid Orbitals} = \frac{1}{2} 	imes (7 + 2 - 0 + 1) = \frac{10}{2} = 5$$A$ hybridization number of $5$ corresponds to $sp^3d$ hybridization.

What is the hybridization of the central $I$ atom in the $I_3^-$ ion?

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