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(B) When an electron transitions from an excited state with principal quantum number $n$ to lower energy levels,the total number of possible spectral

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$6$

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(B) When an electron transitions from an excited state with principal quantum number $n$ to lower energy levels,the total number of possible spectral lines is given by the formula:$N = \frac{n(n - 1)}{2}$Given that the electron is excited to the state $n = 4$,we substitute this value into the formula:$N = \frac{4(4 - 1)}{2}$$N = \frac{4 	imes 3}{2}$$N = \frac{12}{2} = 6$Therefore,the total number of spectral lines emitted is $6$.

$A$ hydrogen atom is excited from the ground state to a state with principal quantum number $n = 4$. The number of spectral lines emitted in the emission spectrum is:

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