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(B) The hydrolysis of $BCl_3$ results in the formation of boric acid $(X)$.$BCl_3 + 3H_2O \longrightarrow H_3BO_3 (X) + 3HCl$When boric acid $(X)$ rea

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$H_3BO_3$ and $Na_2B_4O_7$

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(B) The hydrolysis of $BCl_3$ results in the formation of boric acid $(X)$.$BCl_3 + 3H_2O \longrightarrow H_3BO_3 (X) + 3HCl$When boric acid $(X)$ reacts with sodium carbonate $(Na_2CO_3)$,it produces sodium tetraborate $(Y)$,carbon dioxide,and water.$4H_3BO_3 + Na_2CO_3 \longrightarrow Na_2B_4O_7 (Y) + CO_2 + 6H_2O$Therefore,$X$ is $H_3BO_3$ and $Y$ is $Na_2B_4O_7$.

Hydrolysis of $BCl_3$ gives $X$,which on treatment with sodium carbonate produces $Y$. $X$ and $Y$,respectively,are

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