Benzene xrightarrow{HNO_3/H_2SO_4} Intermedia | vedclass

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(B) $1$. The reaction of benzene with a mixture of concentrated $HNO_3$ and concentrated $H_2SO_4$ (nitrating mixture) undergoes electrophilic aromati

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Aniline

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(B) $1$. The reaction of benzene with a mixture of concentrated $HNO_3$ and concentrated $H_2SO_4$ (nitrating mixture) undergoes electrophilic aromatic substitution to form nitrobenzene as the intermediate.$2$. Nitrobenzene is then reduced using $Sn/HCl$ (a reducing agent) under heating conditions to form aniline $(C_6H_5NH_2)$.$3$. The overall reaction is: $C_6H_6$ $\xrightarrow{HNO_3/H_2SO_4} C_6H_5NO_2$ $\xrightarrow{Sn/HCl, \Delta} C_6H_5NH_2$.

Benzene $\xrightarrow{HNO_3/H_2SO_4}$ Intermediate $\xrightarrow[Heat]{Sn/HCl}$ Product. Identify the final product.

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