Identify X, Y, Z in the following reaction se | vedclass

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(C) $1$. The starting material is propan$-1-$ol $(CH_3CH_2CH_2OH)$.$2$. Oxidation with $CrO_3/H_2SO_4$ (Jones reagent) converts the primary alcohol to

Vedclass · Accepted Answer

$X = CH_3CH_2COCl, Y = (CH_3)_2Cd, Z = HOCH_2CH_2OH/HCl 	ext{ (gas)}$

Vedclass · Answer

(C) $1$. The starting material is propan$-1-$ol $(CH_3CH_2CH_2OH)$.$2$. Oxidation with $CrO_3/H_2SO_4$ (Jones reagent) converts the primary alcohol to propanoic acid $(CH_3CH_2COOH)$.$3$. Treatment with $SOCl_2$ converts the carboxylic acid to propanoyl chloride $(CH_3CH_2COCl)$,which is $X$.$4$. Reaction of $X$ with dimethylcadmium $((CH_3)_2Cd)$ is a standard method to prepare ketones from acid chlorides,yielding butan$-2-$one $(CH_3CH_2COCH_3)$. Thus,$Y = (CH_3)_2Cd$.$5$. The final step is the protection of the ketone as a cyclic acetal using ethylene glycol $(HOCH_2CH_2OH)$ in the presence of dry $HCl$ gas. Thus,$Z = HOCH_2CH_2OH/HCl 	ext{ (gas)}$.$6$. Therefore,option $C$ is correct.

Identify $X, Y, Z$ in the following reaction sequence:

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