Identify X and Y in the following reaction:CH | vedclass

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(A) The reaction proceeds in two steps:Step $1$: Electrophilic addition of $HBr$ to ethene $(CH_2=CH_2)$ gives bromoethane $(CH_3CH_2Br)$. Thus,$X = H

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$HBr, NaI / 	ext{dry } CH_3COCH_3$

Vedclass · Answer

(A) The reaction proceeds in two steps:Step $1$: Electrophilic addition of $HBr$ to ethene $(CH_2=CH_2)$ gives bromoethane $(CH_3CH_2Br)$. Thus,$X = HBr$.Step $2$: Bromoethane reacts with $NaI$ in dry acetone to form iodoethane $(CH_3CH_2I)$ via the Finkelstein reaction. Thus,$Y = NaI / 	ext{dry } CH_3COCH_3$.Therefore,the correct reagents are $X = HBr$ and $Y = NaI / 	ext{dry } CH_3COCH_3$.

Identify $X$ and $Y$ in the following reaction:
$CH_2=CH_2 \xrightarrow[(i) X]{(ii) Y} CH_3CH_2I$

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Identify $X$ and $Y$ in the following reaction:$CH_2=CH_2 \xrightarrow[(i) X]{(ii) Y} CH_3CH_2I$