Identify X, Y and Z respectively from the fol | vedclass

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(A) The reaction sequence is as follows:$1$. $C_2H_2$ (acetylene) when passed through a red hot iron tube undergoes cyclic polymerization to form benz

Vedclass · Accepted Answer

Benzaldehyde,Aniline,$m$-Nitrobenzaldehyde

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(A) The reaction sequence is as follows:$1$. $C_2H_2$ (acetylene) when passed through a red hot iron tube undergoes cyclic polymerization to form benzene. Benzene reacts with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3/CuCl$ (Gattermann-Koch reaction) to form $X$ (Benzaldehyde).$2$. Benzaldehyde $(X)$ reacts with aniline $(Y)$ to form a Schiff's base.$3$. Benzaldehyde $(X)$ undergoes nitration with $HNO_3/H_2SO_4$ at $273 \ K$ to form $Z$ ($m$-nitrobenzaldehyde) because the $-CHO$ group is meta-directing.Therefore,$X$ is benzaldehyde,$Y$ is aniline,and $Z$ is $m$-nitrobenzaldehyde. The correct option is $(a)$.

Identify $X, Y$ and $Z$ respectively from the following reactions:

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