Identify A and B from the following reactions | vedclass

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(A) Step $1$: Ozonolysis of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ yields two molecules of acetaldehyde $(CH_3CHO)$. Thus,$X = CH_3CHO$.Step $2$: Aldol conde

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$CH_3CHO + CHO-CHO$

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(A) Step $1$: Ozonolysis of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ yields two molecules of acetaldehyde $(CH_3CHO)$. Thus,$X = CH_3CHO$.Step $2$: Aldol condensation of $2$ molecules of acetaldehyde $(2CH_3CHO)$ in the presence of dilute $NaOH$ followed by heating $(\Delta)$ gives $but-2-enal$ $(CH_3-CH=CH-CHO)$,which is $Z$.Step $3$: Ozonolysis of $but-2-enal$ $(CH_3-CH=CH-CHO)$ breaks the double bond to form acetaldehyde $(CH_3CHO)$ and glyoxal $(CHO-CHO)$.Therefore,$A$ and $B$ are $CH_3CHO$ and $CHO-CHO$.

Identify $A$ and $B$ from the following reactions:
$(I)$ $CH_3-CH=CH-CH_3 \xrightarrow{\text{(i) } O_3}{\text{(ii) } Zn-H_2O} 2X$
$(II)$ $2X$ $\xrightarrow[2. \Delta]{1. NaOH \text{ (dil.)}} Z$ $\xrightarrow[\text{(ii) } Zn-H_2O]{\text{(i) } O_3} A + B$

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Identify $A$ and $B$ from the following reactions:$(I)$ $CH_3-CH=CH-CH_3 \xrightarrow{\text{(i) } O_3}{\text{(ii) } Zn-H_2O} 2X$$(II)$ $2X$ $\xrightarrow[2. \Delta]{1. NaOH \text{ (dil.)}} Z$ $\xrightarrow[\text{(ii) } Zn-H_2O]{\text{(i) } O_3} A + B$