Identify R', R'' and R''' for the following r | vedclass

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(B) The reaction of a Grignard reagent $(R'''MgX)$ with a ketone $(R'R''C=O)$ produces a tertiary alcohol.The structure of $2-methylbutane-2-ol$ is $C

Vedclass · Accepted Answer

$R'=CH_3, R''=C_2H_5, R'''=CH_3$

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(B) The reaction of a Grignard reagent $(R'''MgX)$ with a ketone $(R'R''C=O)$ produces a tertiary alcohol.The structure of $2-methylbutane-2-ol$ is $CH_3-C(OH)(CH_3)-CH_2-CH_3$.This tertiary alcohol is formed by the nucleophilic addition of a Grignard reagent to a ketone.If we react butan$-2-$one $(CH_3-CO-C_2H_5)$ with methylmagnesium bromide $(CH_3MgBr)$, the methyl group $(CH_3)$ attacks the carbonyl carbon, resulting in $2-methylbutane-2-ol$.Comparing this with the general reaction $R'R''C=O + R'''MgX \rightarrow R'R''C(OH)R'''$, we identify $R'=CH_3$, $R''=C_2H_5$, and $R'''=CH_3$.

Column-$I$ (Name)	Column-$II$ (Structure)	Column-$III$ (Source)
$(A)$ Vanillin	$(i)$ $C_6H_4(OH)CHO$ (ortho)	$(p)$ From cinnamon
$(B)$ Salicylaldehyde	$(ii)$ $C_6H_5CH=CHCHO$	$(q)$ From seeds of vanilla
$(C)$ Cinnamaldehyde	$(iii)$ $C_6H_3(OH)(OCH_3)CHO$	$(r)$ From meadow sweet

Identify $R', R''$ and $R'''$ for the following reaction: $R'R''C=O \xrightarrow{(i) R'''MgX, (ii) H_2O} 2-methylbutane-2-ol$

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