Identify 'Z' in the following reaction: Ar-OH | vedclass

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(B) Step $1$: The reaction between a phenol $(Ar-OH)$ and an acid chloride $(R-COCl)$ in the presence of a base like pyridine is known as the Schotten

Vedclass · Accepted Answer

$Ar-O-C(=O)-R$

Vedclass · Answer

(B) Step $1$: The reaction between a phenol $(Ar-OH)$ and an acid chloride $(R-COCl)$ in the presence of a base like pyridine is known as the Schotten-Baumann reaction.Step $2$: The lone pair on the oxygen atom of the phenol attacks the electrophilic carbonyl carbon of the acid chloride.Step $3$: The chloride ion $(Cl^-)$ acts as a leaving group, and the pyridine neutralizes the $HCl$ produced to drive the reaction forward.Step $4$: The product formed is an ester, specifically an aryl ester, with the structure $Ar-O-C(=O)-R$.

Identify '$Z$' in the following reaction: $Ar-OH + Cl-C(=O)-R \xrightarrow{\text{Pyridine}} Z + HCl$

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