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(A) $1$. The reaction of benzene with conc. $HNO_3$ and conc. $H_2SO_4$ (nitration) yields $A = 	ext{Nitrobenzene}$.$2$. Nitrobenzene is a meta-direc

Vedclass · Accepted Answer

$A = 	ext{Nitrobenzene}$,$B = m	ext{-Chloronitrobenzene}$,$C = m	ext{-Chloroaniline}$

Vedclass · Answer

(A) $1$. The reaction of benzene with conc. $HNO_3$ and conc. $H_2SO_4$ (nitration) yields $A = 	ext{Nitrobenzene}$.$2$. Nitrobenzene is a meta-directing group. Therefore,chlorination of nitrobenzene using $Cl_2$ and anhydrous $AlCl_3$ gives $B = m	ext{-Chloronitrobenzene}$.$3$. The reduction of the nitro group $(-NO_2)$ in $m	ext{-Chloronitrobenzene}$ using $Fe/HCl$ yields $C = m	ext{-Chloroaniline}$.

Identify the correct $A$,$B$,and $C$ in the reaction sequence given below:

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