Identify product $A$ in the following reaction:
$C_6H_5N_2^+Cl^- \xrightarrow{C_2H_5OH} A + N_2 + CH_3CHO + HCl$

Which of the following represents the correct order of basicity in an aqueous medium?

For the diazonium ions,the order of reactivity towards the diazo-coupling with phenol in the presence of dilute $NaOH$ is:
$(I)$ $Me_2N-C_6H_4-N_2^+$
$(II)$ $O_2N-C_6H_4-N_2^+$
$(III)$ $CH_3O-C_6H_4-N_2^+$
$(IV)$ $CH_3-C_6H_4-N_2^+$

The number of compounds from the following which can undergo reaction with $Br_2/KOH$ (alcoholic) to give respective products, and these respective products can also be obtained separately by the Gabriel phthalimide synthesis, is:

In the carbylamine reaction,the number of moles of $KOH$ and $CHCl_3$ used per mole of isocyanide produced are $X_1$ and $X_2$ respectively. Find out $X_1 - X_2$.

Which of the following is most reactive towards electrophile?