Identify D and E in the following reaction: C | vedclass

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Question

(A) The product of the Wurtz reaction is $2,3$-dimethylbutane $(CH_3-CH(CH_3)-CH(CH_3)-CH_3)$. This indicates that the starting alkyl bromide $R'-Br$

Vedclass · Accepted Answer

$D 	o CH_3-CH(MgBr)-CH_3, E 	o CH_3-CH_2-CH_3$

Vedclass · Answer

(A) The product of the Wurtz reaction is $2,3$-dimethylbutane $(CH_3-CH(CH_3)-CH(CH_3)-CH_3)$. This indicates that the starting alkyl bromide $R'-Br$ is isopropyl bromide $(CH_3-CH(Br)-CH_3)$.Step $1$: $2 CH_3-CH(Br)-CH_3 + 2 Na \xrightarrow{ether} CH_3-CH(CH_3)-CH(CH_3)-CH_3 + 2 NaBr$.Step $2$: $CH_3-CH(Br)-CH_3 + Mg \xrightarrow{ether} CH_3-CH(MgBr)-CH_3$ $(D)$.Step $3$: $CH_3-CH(MgBr)-CH_3 + H_2O 	o CH_3-CH_2-CH_3$ $(E)$ $+ Mg(OH)Br$.Therefore,$D$ is isopropyl magnesium bromide and $E$ is propane.

Identify $D$ and $E$ in the following reaction: $CH_3-CH(CH_3)-CH(CH_3)-CH_3 \xleftarrow[ether]{Na} R'-Br$ $\xrightarrow{Mg} D$ $\xrightarrow{H_2O} E$

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